Skip to main content

ABCD is a parallelogram | Prove that ∆ BCF and ∆ DFE are equal in area

ABCD is a parallelogram , a line trhough A cuts DC at oint F and BC produced at E Prove that ∆ BCF is equal in area to ∆ DFE.

Construction: AC is joined.


AB || CD and AD || BC .
Now ∆ ACE and ∆ DCE are on the same base CE and between sane parallel lines AD and AE . Therefore
∆ ACE = ∆ DCE
∆ ACE - ∆ FCE = ∆ DCE - ∆ FCE
∴ ∆ ACF = ∆ DFE
Now ∆ ACF and ∆ BCF are on the same base and between same parallel .
∴ ∆ ACF = ∆ BCF
∴ ∆ DFE = ∆ BCF

Proved

You may also Like These !

Comments





Weekly Popular

Question Answer of 'Daffodils' | English Literature